To practice problem-solving strategy 21.1 coulomb's law. three charged particles are placed at each of three corners of an equilateral triangle whose sides are of length 2.3 cm . two of the particles have a negative charge: q1 = -6.7 nc and q2 = -13.4 nc . the remaining particle has a positive charge, q3 = 8.0 nc . what is the net electric force acting on particle 3 due to particle 1 and particle 2?

241.27 N

Explanation:

Both the negative charge will pull the positive charge towards it . Let the forces be F₁ and F₂

F₁ =

F₁ = 91.19 X 10⁻⁵ N

F₂=

F₂ = 182.38 X 10⁻⁵ N

F₁ and F₂ act at 60 degree so their resultant will be calculated as follows

R² = (91.19)² +(182.38)² + 2 X 91.19 X 182.38 Cos 60

R² = 58209.30

R = 241.27 N

answer

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explanation:

answer: point c: b. 1/2 potential, 1/2 kinetic, point a: 3/4 of its potential energy, point d or b: 3/4 potential, 1/4 kinetic

explanation: i cant explain. it's difficult to explain.