Your school science club has devised a special event for homecoming. you’ve attached a rocket to the rear of a small car that has been decorated in the green and gold school colors. the rocket provides a constant acceleration for 9.0 s. as the rocket shuts off, a parachute opens and slows the car at a rate of 5.0 m/s2 . the car passes the judges’ box in the center of the grandstand, 990 m from the starting line, exactly 12 s after you fire the rocket. what is the car’s speed as it passes the judges

V=120m/s

Explanation:

A body that moves with constant acceleration means that it moves in "a uniformly accelerated movement", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.

Vf=Vo+a.t                                     (1)

{Vf^{2}-Vo^2}/{2.a} =X                (2)

X=Xo+ VoT+0.5at^{2}                   (3)

X=(Vf+Vo)T/2                                 (4)

Where

Vf = final speed

Vo = Initial speed

T = time

A = acceleration

X = displacement

In conclusion to solve any problem related to a body that moves with constant acceleration we use the 3 above equations and use algebra to solve

for this problem you must divide the problem into two parts 1 and 2, when the rocket accelerates (1), and when the rocket decelerates (2).

Then you raise equations 3 and 1 in both parts.

finally you use algebraic methods to find the value of speed

I attach the complete procedure

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//