Assuming that a rabbit runs at a speed of 12.0 meters per second. how far would the rabbit travel in 11.5 seconds? a hiker takes a hiking trip around the camp. he first travels 5.10 km in one hour at a constant speed. he then travels 16.5 km in two hours at a different constant speed and reaches a ranch tower. what is the average speed of the hiker for the entire trip?

(A). The rabbit travel the distance 138 m.

(B). The average speed of the hiker for the entire trip is 7.2 km/h.

Explanation:

Given that,

Speed = 12.0 m

Time = 11.5 second

(A). We need to calculate the distance

Using formula of distance

The rabbit travel the distance 138 m.

(B). Given that,

Distance = 5.10 km

Time = 1 hours

Distance 16.5 km

Time = 2 hours

We need to calculate the average speed of the hiker for the entire trip

Using formula of average speed

Where, D = Total distance

T = Total time

Put the value into formula

The average speed of the hiker for the entire trip is 7.2 km/h.

Hence, This is the required solution.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

a cold ice-tea.

pour in room temperature or cold water. cover the pitcher and refrigerate. steep white or green tea for 6 to 8 hours; steep black or oolong tea for 8 to 12 hours.jun 28, 2015