The total length of the cord is l = 7.00 m, the mass of the cord is m = 7.00 g, the mass of the hanging object is m = 2.50 kg, and the pulley is a fixed a distance d = 4.00 m from the wall. you pluck the cord between the wall and the pulley and it starts to vibrate. what is the fundamental frequency (in hz) of its vibration?

frequency = 19.56 Hz

Explanation:

given data

length L = 7 m

mass m = 7 g

mass M = 2.50 kg

distance d = 4 m

to find out

fundamental frequency

solution

we know here frequency formula is

frequency =   ...........1

so here d is given = 4

and v =  ..........2

tension T = Mg = 2.50 × 9.8 = 24.5 N

and μ = =   = kg/m

so from equation 2

v =

v = 156.52

and from equation 1

frequency =

frequency =

frequency = 19.56 Hz

it was given as a lesson and guide for prayer.

explanation:

wheres the pic