Aswan on a lake becomes airborne by flapping its wings and running on top of the water. if the swan must reach a velocity of 6.50 m/s to take off and it accelerates from rest at an average rate of 0.350 m/s2 , what distance δx does it travel before becoming airborne?

The distance traveled by the swan is 60.35 meters.

Explanation:

Given that,

A swan accelerate from rest (u = 0) to 6.5 m/s to take off.

Acceleration of the swan,

We need to find the distance Δx it travel before becoming airborne. From the third equation of motion as :

So, the distance traveled by the swan is 60.35 meters. Hence, this is the required solution.

hey , the answer is c

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west