In a crash test, a 2,500 kg car hits a concrete barrier at 1.3 m/s2. if the car strikes the barrier with a force of 3,250 n, how much resistance force does the barrier provide? n this pair of forces is an example of newton's law of motion.

3250 N in the opposite direction

Explanation:

According to Newton's third law of motion:

"Each action has an equal and opposite reaction"

To understand it better:  

When two bodies interact between them, appear equal forces and opposite senses in each of them.  For example, if a body A exerts a force on another body B, it performs on A another force with the same magnitude and in the opposite direction.

Hence, this law states that for each force acting on a body, ther is a force of equal intensity but in the opposite direction on the body that produced it.

In this sense if the car hit the concrete barrier with a force of 3250 N, the concrete barrier will exert a force of -3250 N on the car (where the negative sign indicates the force is acting in the opposite direction).

i think the answer is a, hope this is right, that would be my best guess.