Vector l is 303m long in a 205 direction. vector m is 555m long in a 105 direction. find the magnitude and direction of the vector.

584.3 m at above the positive x-axis

Explanation:

We have to find the magnitude and direction of the resultant vector. In order to do that, we have to resolve each vector along the x- and y- direction first.

Resolving the vector L:

Resolving the vector M:

Now we can find the components of the resultant vector by adding the components of each vector along each direction:

So the magnitude of the resultant vector is

While the direction is given by:

But since is negative and is positive, it means that this angle is measured as angle above the negative x-axis; so the direction of the vector is actually

it becomes positively charged by charging it

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s