As a hurricane passes through a region, there is an associated drop in atmospheric pressure. if the height of a mercury barometer drops by 21.4 mm from the normal height, what is the atmospheric pressure (in pa)? normal atmospheric pressure is 1.013 ✕ 105 pa and the density of mercury is 13.6 g/cm3 (note: this is g/cm^3, not si units of kg/m^3).

The atmospheric pressure is

Explanation:

There are two ways of solving this exercise:

1)

In physics you can find that mmHg is a unit of pressure.

Pressure = Force/area.

If you consider the weight of mercury as your force (mass* acceleration of gravity = density*volume* acceleration of gravity ), then

where h is the height of the mercury column and rho its density.

.

if normal atmospheric pressure is

then the pressure in the presence of the hurricane is

2)

Considering the definition of pressure

where , and .

, where .

if

,

then

.

this a false

explanation: