The burner on an electric stove has a power output of 2.0 kw. an 810 g stainless steel tea kettle is filled with water at 20∘ c and placed on the already hot burner. if it takes 2.4 min for the water to reach a boil, what volume of water was in the kettle? stainless steel is mostly iron, so you can assume its specific heat is that of iron.

volume of water in the kettle, V =

Given:

Power output of burner, P = 2.0 kW = 2000 W

Mass of kettle, m = 810 g = 0.81 kg

Temperature of water in the kettle, T =

Time taken by water to boil, t = 2.4 min = 144 s

Temperaturre at boiling, T' =

Solution:

Now, we know that:

Iron's specific heat capacity,

Water's specific heat capacity,

Now,

Total heat, q = Pt

q =

Now,

q = (mc +m'c')(T' - T)

Solving the above eqn m', we get:

m' = 774 g

Now, the volume of water in the kettle, V:

where

Now,

Volume, V =

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