Two point charges are separated by a distance of 30.0 cm. the numerical value of one charge is twice that of the other. each charge exerts a force of magnitude 65.0 n on the other.
find the magnitude of the charge with a greater magnitude.

The charge with greater magnitude =

Explanation:

We have the distance between two charges = 30 cm = 0.3 m

Force between two charges = 65 N

Let the first charge be q

Then according to question second charge will be 2q

According to coulombs law force between two charges

Where K is constant which value is

So

So larger charge

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

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