Physics, 07.09.2019 20:10 masonballard7266
The resistanceless inductor is connected across the ac source whose voltage amplitude is 24.5 v and angular frequency is 850 rad/s . find the current amplitude if the self-inductance of the inductor is: part a: 1.00×10−2 h . answer in a.
part b: 1.00 h . answer in ma.
part c: 100 h . answer in ma.
Answers: 1
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The resistanceless inductor is connected across the ac source whose voltage amplitude is 24.5 v and...
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