Two parallel plates are charged with 7.58*10^-9 c of charge. what must the area of the plates be to create an electric field of 47500 n/c? (unit = m^2)

area of the plates is 0.01802 m²

Explanation:

given,

charge between the plate = 7.58 × 10⁻⁹ C

electric field = 47500 N/C

E =

V = E× d

charge on the plate

 Q = C V

Q =

Q = ∈₀ × A × E

A =

A =

A = 0.01802 m²

hence, area of the plates is 0.01802 m²

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