Light propagating in air strikes the surface of a lake. the reflected ray makes 62° angle with the normal. what angle does the refracted ray in the water makes with the normal. (hint: index of refraction for water 1.33) (a) 42° (b) 48° (c) 54° (d) 58°

(a) 42°

Explanation:

According to the law of reflection:

Angle of incidence = Angle of reflection

So, angle of reflection = 62°

Angle of incidence = 62°

For refraction,

Using Snell's law as:

Where,  

 is the angle of incidence  ( 62.0° )

is the angle of refraction  ( ? )

is the refractive index of the refraction medium  (water, n=1.33)

is the refractive index of the incidence medium (air, n=1)

Hence,  

Angle of refraction = = 42°

f is prop to m1xm2 double m1 double force

if they have a finite resultant