Two resistors, 200ω and 300ω are in parallel: a) find their equivalent resistance b) the parallel combination is connected to a 12v battery. find the current out of the battery c) find the current flowing in each resistor.

(A) R =120 ohm (b) 0.1 A (C) current through 200 ohm is 0.06 A and current through 300 ohm is 0.04 A

Explanation:

We have two resistances

(a) As the resistances are connected in parallel

So

(b) The combination is connected through 12 V battery

So current

(C) According to current division rule

Current through 200 ohm resistor

Now current through 300 ohm resistor = 0.1-0.06=0.04 A

a) 120 Ω

b) 0.1 A

c) 0.06 A , 0.04 A

Explanation:

Given:

Resistance R₁ and R₂ = 200 ohms and 300 ohms

Potential difference or voltage = V = 12 V

a) When resistors are in parallel, the equivalent resistance is given by the formula

⇒ R =

       = = (0.00833)⁻¹

⇒ Equivalent resistance = R = 120 ohms.

b) Current out of the battery = I = V/R = 12/120 = 0.1 A.

c) Since the resistors are in parallel, Voltage across each is equal to 12V.

Current flowing in R₁ = V/R₁ = 12 /200 = 0.06 A

Current flowing in R₂ = V/R₂ = 12 /300 = 0.04 A

does anyone know or what?