In a circuit consisting of two light bulbs that are connected in series, where 6 v were impressed across the circuit and the voltage across the first bulb is 2 v then the
voltage across the second bulb would be

4 V

Explanation:

For the series circuit, the resultant, R of the resistors, say R₁ and R₂ is:

R = R₁ + R₂

Since, in the series circuit, the magnitude of the current remains same for each resistor. Thus, multiplying both side by I.

I×R = I×R₁ + I×R₂

Also, according to the Ohm's law, V = I × R

So,

V = V₁ + V₂

Given that:

V = 6 V

V₁ = 2 V

So, V₂ is:

6 V = 2 V + V₂

V₂ = 4 V