Aclosed system containing an ideal gas undergoes an isentropic expansion process followed by a constant volume heat rejection process. both processes are reversible. assuming constant specific heat, write an equation for heat transfer and work for each process.

For isentropic process : Q= 0 ,

For constant volume : ,W=0

Explanation:

Given that:

System is closed

In first process ideal gas goes an isentropic expansion and then constant volume heat rejection.

We know that from first law of thermodynamic

Q = ΔU +  W

For process 1-2:

Process is adiabatic it means that Q=0

So  Q = ΔU +  W

0 =  ΔU +  W

W= -ΔU

We know that internal energy for ideal gas

So work W

For process 2-3:

Process is constant volume so work transfer will be zero ,W=0

Q = ΔU +  W

Q = ΔU +  0

Q = ΔU

depends on what you mean by "group." for order, it would be coleoptera (beetles). for class, it would be insecta (insects). for phylum, it would be the arthropoda (animals with jointed exoskeletons).

explanation:

answer:   you might love summer weather, but you don’t want it to feel like the sun is inside your car. but a hot car that just won’t seem to cool down might be a bigger of a problem than you think. your car relies on being at the right temperature.

explanation: