Calculate the density of the air at the top of mt everest given the pressure is 278 hpa and the temperature is-43.2°c (you may ignore the effect of water vapour on density for this problem).

density of air at the top of Mt Everest is

Explanation:

using ideal gas equation

   P V = n R T...........(1)

  molecular weight of gas

    n =

volume  V =

therefore from equation (1)

hence, density of air at the top of Mt Everest is

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form