Akangaroo jumps straight up with an initial vertical velocity of 2.4\,\dfrac{\text{m}}{\text{s}}2.4 sm 2, point, 4, space, start fraction, m, divided by, s, end fraction. we want to find the maximum height of the jump.

it can jump upto maximum height of 0.29 m

Explanation:

Initial velocity of the Kangaroo when it jumps upwards is given as

final velocity of the kangaroo is given as

now we know that acceleration is due to gravity

now in order to find maximum height we know that we can use kinematics equation

so it can jump upto maximum height of 0.29 m

15.3 cos 65 degrees trig

your answer is, orbit around the nucleus