What is the relation between the wavelength, λ, and the momentum, p, of a particle? roughly what kinetic energy should an electron have in order for its wavelength be of roughly an "atomic" distance scale? re-express this as the number of volts needed to accelerate that electron from rest to this energy. would you call this a high-voltage device?

λ = h/p

This energy is equivalent to E=150.44eV

Explanation:

de Broglie Equation:

λ = h/p

h=6.63×10-34 m2 kg / s        Planck's constant

so: p=h/λ

On the other hand, an atomic distance, an angstrom, is equal:, λ should be similar to this distance.

Kinetics Energy of a electron, m=9.11×10−31 kg

Number of volts needed to accelerate that electron from rest to this energy:

So, this energy is equivalent to E=150.44eV

This high-voltage device is called: particles accelerator

i think the answer would be reserve.

report!

explanation:

physics means: "the branch of science concerned with the nature and properties of matter and energy. the subject matter of physics, distinguished from that of chemistry and biology, includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms."