If a construction worker drops a wrench from the top of a building 450 feet high the wrench will be s(t) = −16t 2 + 450 feet above the ground after t seconds. determine the velocity of the wrench 2 seconds after it was was dropped. answer in units of ft/sec.

We know that the rate of change of the position of a given object is equal to the velocity of that object.

We will find that the velocity of the wrench after 2 seconds is -64ft/s

Now we know that the height (vertical position) of the wrench is:

s(t) = -16*t^2 + 450

Then to get the velocity equation we need to differentiate this, remember the general rule:

Then we will get that the velocity equation is:

v(t) = 2*(-16)*t + 0

v(t) = -32*t

And because the position is in ft, this velocity will be in ft per second.

Then the velocity of the wrench 2 seconds after it was dropped is given by:

v(2) = -32*2 = -64

Then the velocity of the wrench after 2 seconds is -64ft/s

If you want to learn more, you can read:

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-64ft/s

Explanation:

Given:

Unknown:

For t = 2:

igneous rocks also form where plates converge. the subducting plate melts as it sinks into the crust of the earth, and the melt rises into the overriding plate forming volcanoes. metamorphic rocks are formed mainly in the lithosphere, wherever there is high pressure and high temperature. -woods

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form