Calculate the number of free electrons and holes (in m-3) in an intrinsic semiconductor that has electron and hole mobilities of 0.35 and 0.17 m2/v-s, respectively, and a conductivity of 1.7 (ω-m)-1. use scientific notation.

ni = 2.04e19

Explanation:

we know that in semiconductor like intrinsic, when electron leave the band, it leave a hole in valence band so we have

n = p = ni

from intrinsic carrier concentration

1.7 = ni * 1.6*10^{-19} * (.35 + .17)

ni = 2.014 *10^{19} m^{-3}

ni = 2.04e19

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.

close lines strong magnet less close weaker