Water is heated in an insulated, constant diameter tube by a 11-kw electric resistance heater. if the water enters the heater steadily at 15°c and leaves at 70°c, determine the mass flow rate of the water. consider the specific heat of water at room temperature is cp = 4.18 kj/kg·°c.

The mass flow rate of water is 0.0478 kg/s or 47.8 g/s

Explanation:

We have:

Power of electric heater = P = 11 KW

Change in temperature of water = ΔT = 70°C - 15°C = 55°C

Specific heat of water = C = 4.18 KJ / kg.°C

Now, from conservation of energy, we know that:

Energy dissipated by heater = Energy acquired by Water

Energy dissipated by heater = m C ΔT

Dividing both sides by time (t), we get:

Power of Heater = (mass flow rate) C ΔT

Mass Flow Rate = P/CΔT

Mass Flow Rate = (11 KW)/(4.18 KJ/kg.°C)(55°C)

Mass Flow Rate = 0.0478 kg/s = 47.8 g/s

explanation:

to push or pull an object in a certain direction is known as force. a force in moving an object from one place to another.

force depends on the mass of an object. so, more is the mass of an object more will be the force required to move the object.

thus, we can conclude that the use of force to move an object is push or pull.