An electron is located on the x axis at x0 = -8.27 × 10-6 m. find the magnitude and direction of the electric field at x = 1.67 × 10-6 m on the x axis due to this electron. magnitude:

The magnitude of the electric field at the given point is 14.57 N/C and the direction of the electric field is negative x- direction

Explanation:

Given that,

Electron located on the x axis is

Electric field at a point on the x axis is

Magnitude of charge

We need to calculate the distance between  the electron and the point

Put the value into the formula

We need to calculate the magnitude of the electric field

Using formula of electric field

Put the value into the formula

The direction of the electric field is negative x- direction because the direction of force on the charge at a given point on the x-axis.

Hence, The magnitude of the electric field at the given point is 14.57 N/C and the direction of the electric field is negative x- direction

correct it is c.) b b

b mirrors submit a iisner? e. for which optical devices does d sometimes have a positive value? o a a and b o b. a and c o c. b and d 0 d. b and cb