Acar traveling north slows down from 40 m/s to rest in a distance of 100 m. what was the magnitude of its average acceleration in m/s^2? and what direction of the car or is there not enough information?

8 m/s² south

Explanation:

Given:

v₀ = 40 m/s

v = 0 m/s

Δx = 100 m

Find: a

v² = v₀² + 2a (x − x₀)

0² = 40² + 2a (100)

a = -8

The acceleration is 8 m/s² south.

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

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