Ateacher pulls a box of books on a horizontal floor with a force of 290 n directed 40.9 degrese above the horizontal. the coefficiant of kinetic friction between the box and the floor is 0.184. the mass of the box and books is 44.5 kg. draw a free body diagram. what is the normal force that the floor exerts on the box? calculate the acceleration of the box

acceleration  is 4.92 m/s²

Explanation:

given data

force F = 290 N

angle  = 40.9°

kinetic friction μ  = 0.184

mass m = 44.5 kg

to find out

acceleration a

solution

we get here force equation that is

Fsinθ = Normal force   ...............a

290 sin40.9  = Normal force

Normal force = 189.87 N

and

Fcosθ - μ = m×a    ................b

put here all value

290 cos40.9 - 0.184 = 44.5 a

a = 4.92

so acceleration  is 4.92 m/s²

are their multiple choices ?

explanation:

the answer is a. at the equator