A10-turn coil of wire having a diameter of 1.0 cm and a resistance of 0.50 ω is in a 1.0 mt magnetic field, with the coil oriented for maximum flux. the coil is connected to an uncharged 1.0 μf capacitor rather than to a current meter. the coil is quickly pulled out of the magnetic field. afterward, what is the voltage across the capacitor? hint: use i =dq/dt to relate the net change of flux to the amount of charge that flows to the capacitor.
express your answer with the appropriate units.

The voltage across the capacitor is 1.57 V.

Explanation:

Given that,

Number of turns = 10

Diameter = 1.0 cm

Resistance = 0.50 Ω

Capacitor = 1.0μ F

Magnetic field = 1.0 mT

We need to calculate the flux

Using formula of flux

Put the value into the formula

We need to calculate the induced emf

Using formula of induced emf

Put the value into the formula

Put the value of emf from ohm's law

We know that,

We need to calculate the voltage across the capacitor

Using formula of charge

Put the value into the formula

Hence, The voltage across the capacitor is 1.57 V.

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.