Enceladus is a moon of saturn. its radius is 2.52 x 10^25 m and its mass is 1.08 x 10^20 kg. what is the acceleration of gravity on its surface? on its

0.113 m/s²

Explanation:

Acceleration due to an object's gravity is:

g = GM / R²

where G is the universal gravitational constant (6.67×10⁻¹¹ m³/kg/s²),

M is the mass of the object,

and R is the distance from the object's center of mass.

Given M = 1.08×10²⁰ kg and R = 2.52×10⁵ m:

g = (6.67×10⁻¹¹ m³/kg/s²) (1.08×10²⁰ kg) / (2.52×10⁵ m)²

g = 1.13×10⁻¹ m/s²

The acceleration of gravity on the surface of Enceladus is 0.113 m/s².