A200-turn rectangular coil having dimensions of 3.0 cm by 6.0 cm is placed in a uniform magnetic field of magnitude 0.76 t. (a) find the current in the coil if the maximum torque exerted on it by the magnetic field is 0.14 n · m. a (b) find the magnitude of the torque on the coil when the magnetic field makes an angle of 25° with the normal to the plane of the coil. n · m

(a). Current, I = 0.512 A = 512 mA

(b). Torque,

Given:

Number of turns in the rectangular coil, n = 200 turns

Area of the coil with dimensions 3.0 cm by 6.0 cm, A =

Intensity of magnetic field, B = 0.76 T

maximum torque,

angle,

Solution:

(a) Current in the coil, I can be calculated by the given relation:

Therefore,

Now substituting the given values in the above eqn:

I = 0.512 A = 512 mA

(b)  Magnitude of torque can be calculated by the given relation:

Now,

where's the following? you gotta add it to know what the choices are

explanation:

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.