Consider a hydrogen atom in the n = 1 state. the atom is placed in a uniform b field of magnitude 2.5 t. calculate the energy difference between the highest and lowest electronic energy levels in the presence of the b field. a. 9.3 x 10^-5 ev
b. 29 x 10^-5 ev
c. 11.6 x 10^-5 ev

Explanation:

For n-=1 state hydrogen energy level is split into three componets in the presence of external magnetic field. The energies are,

,

,

Here, E is the energy in the absence of electric field.

And

are the highest and the lowest energies.

The difference of these energies

is known as Bohr's magneton.

B=2.5 T,

Therefore,

Now,

Therefore, the energy difference between highest and lowest energy levels in presence of magnetic field is

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