Ahorizontal string is attached at one end to an electrical vibrator of frequency 50.0 hz, and at the other to a set of hanging masses. the string has a mass per unit length 0.115 gm^-1. when the string has a length 210.4 cm five loops are observed. what mass (in grams) is hung from the string? you adjust the frequency so that you now observe 4 loops on the string leaving the hanging mass and string length the same. what is the new frequency?

The mass of the string and new frequency are 20.78 g and 40.0 Hz.

Explanation:

Given that,

Frequency = 50.0 Hz

Mass per unit length = 0.115 g/m

String length = 210.4 cm

Number of loops = 5

We need to calculate the mass is hung from the string

Using formula of frequency

Where, f = frequency

M = mass per unit length

T = tension

Put the value into the formula

We need to calculate the new frequency for 4 loops

Using formula of frequency

Hence, The mass of the string and new frequency are 20.78 g and 40.0 Hz.

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr