Adime is placed in front of a concave mirror that has a radius of curvature r = 0.40 m. the image of the dime is inverted and two times the size of the dime. determine the distance between the dime and the mirror.

distance between the dime and the mirror, u = 0.30 m

Given:

Radius of curvature, r = 0.40 m

magnification, m = - 2 (since,inverted image)

Solution:

Focal length is half the radius of curvature, f =

f =

Now,

m = -

- 2 = -

= 2                  (2)

Now, by lens maker formula:

v =            (3)

From eqn (2):

v = 2u

put v = 2u in eqn (3):

2u =

2 =

2(u - 0.20) = 0.20

u = 0.30 m

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .