Aconverging lens (f1 = 12.1 cm) is located 32.4 cm to the left of a diverging lens (f2 = -5.4 cm). a postage stamp is placed 34.5 cm to the left of the converging lens. locate the final image of the stamp relative to the diverging lens.

The final image of the stamp relative to the diverging lens is 7.01 cm to the left side of the diverging lens.

Explanation:

Given that,

Focal length of converging lens = 12.1 cm

Focal length of diverging lens = -5.4 cm

Object distance = 34.5 cm

We need to calculate the image distance for converging lens

Using lens formula

Put the value into the formula

We need to calculate the image distance for diverging lens

Object distance is

Using lens formula

Put the value into the formula

Hence, The final image of the stamp relative to the diverging lens is 7.01 cm to the left side of the diverging lens.

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.