Aspherical conductor of 9-cm radius is charged to 100 volt potential. calculate the energy stored in it.

The energy stored in the conductor is 5×10^-8 J.

Explanation:

let v be the potential of the conductor.

let Q be the charge on the conductor.

let k = 9×10^9 be the coulomb constant.

let r be the radius of the conductor.

then, the potential of the conductor is given by:

V = k×Q/r

Q = V×r/k

   = [(100)×(9×10^-2)]/(9×10^9)

   = 1×10^-9 C

then, the energy stored in the conductor is given by:

E = 1/2×Q×V

  = 1/2×(1×10^-9)×(100)

  = 5×10^-8 J

Therefore, the energy stored in the conductor is 5×10^-8 J.

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