Agenerator produces 10 a at 600v. the primary coil in a transformer has 20 turns. a) how many secondary turns are needed to step up the voltage to 2400v? b) the transformer is connected to a power line whose resistance is (12 ohm). how much of the nower smission line?

no of secondary turns are 80 turns

power is 4.8 × W

Explanation:

given data

current = 10 A

voltage v1 = 600 V

no of turns n1 = 20 turn

voltage v2 = 2400 V

resistance R = 12 ohm

to find out

How many secondary turns  and how much power lost submission line

solution

we find first no of secondary turns that are

n2 / n1 = v2 / v1

put here all value

n2 = 2400 / 600 × 20

n2 = 80

so  no of secondary turns are 80 turns

and

power formula that is

power = v2² / R

put here all value

power = v2² / R

power = 2400² / 12

power = 480000 W

so power is 4.8 × W

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