Afish appears to be 2.00 m below the surface of a pond (nwater = 1.33) when viewed almost directly above by a fisherman. what is the actual depth of the fish?

Explanation:

The given data is as follows.

     Apparent depth = 2.00 m,  refractive index = 1.33

It is known that formula to calculate real depth is as follows.

   The refractive index =

or,       real depth = refractive index × apparent depth

Now, putting the given values into the above formula as follows.

               real depth = 1.33 × 2

                                 = 2.66 m

Thus, we can conclude that the actual (real) depth of the fish is 2.66 m.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft