What is the direction of the current in the loop as the loop rotates clockwise through the magnetic field from as viewed from the top. answer as you face the loop as it opens towards you.

The direction of the current in the loop is explain with the right hand rule, which is a bout the cross product of two vector, which results is another vector but perpendicular with the initial two.

In this case, the magnetic field has to be perpendicular to the rotation of the current in the loop. Now, you can observe that the magnetic field is towards south in the graph. If we apply right-hand rule, we find that the rotation of the current has to be from west to east, that is, from front of the back of the image.

The image attached shows the right-hand rule.

If the magnetic field were towards North, then the current would rotate in the opposite direction, from East to West.

it is easily magnetized.

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: