Physics, 27.08.2019 21:10 potato1458
A1000-kg object hangs from the lower end of a steel rod 5.0 m long that is suspendedvertically. the diameter of the rod is 0.80 cm and young's modulus for the rod is210,000 mn/m2. what is the elongation of the rod due to this object
Answers: 2
m
= mass of the object = 1000 kg 
= weight of the object hanged from rod = 
= 
= 
N 
= length of the steel rod = 5 m 
= elongation of length of the steel rod = ?
= young's modulus of steel = 210,000 MN/m² = 2.1 x 10¹¹ N/m²
= diameter of the rod = 0.80 cm = 0.0080 m 
= Area of cross-section of rod = 
= 
= 50.24 x 10⁻⁶ m²
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A1000-kg object hangs from the lower end of a steel rod 5.0 m long that is suspendedvertically. the...
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