Asubstance has a vapor pressure of 77.86 mm hg at 318.3 k and a vapor pressure of161.3 mmhg at 340. 7 k. calculate its heat of vaporization in kj/mol.

Explanation:

It is given that,

Initial vapor pressure, P₁ = 77.86 mm

Initial temperature, T₁ = 318.3 K

Final vapor pressure, P₂ = 161.3 mm

Initial temperature, T₂ = 340.7 K

We need to find its heat of vaporization. It can be calculated by using Clausius-Clapeyron equation.

So, the heat of vaporization of a substance is 29.31 kJ/mol. Hence, this is the required solution.