At 213.1 k a substance has a vapor pressure of 45.77 mmhg. at 243.7 k it has a vapor pressure of 193.1 mm hg. calculate its heat of vaporization in kj/mol.

kJ/mol

Explanation:

= initial vapor pressure = 45.77 mm Hg

= final vapor pressure = 193.1 mm Hg

= initial temperature = 213.1 K

= final temperature = 243.7 K

= Heat of vaporization

Using the equation

J/mol

kJ/mol

increase masses, decrease separation