Ahill that has a 36.1% grade is one that rises 36.1 m vertically for every 100.0 ml of distance in the horizontal direction. at what angle is such a hill inclined above the horizontal?

angle is 19.85°

Explanation:

given data

grade = 36.1 %

vertically distance y = 36.1 m

horizontal distance x = 100 m

to find out

angle

solution

we know that according to question here

it make a triangle shape that contain 100 m base and height 36.1 m

and make angle with base is θ

so by triangle we know here

tanθ = y/x   1

so we now put x and y and find θ

tanθ = 36.1 / 100

tanθ = 0.361

θ = 19.85°

so angle is 19.85°

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s