Aspherically symmetric charged distribution has a charged density given by ρ = a / r, where a is a constant. find the field within the sphere as a function of r. [

Electric field,

Given:

charge density,

a = constant

Solution:

Area of sphere =

Small charge dq on a sphere of thickness r is:

dq =

dq =             (1)

Integrating both the sides, we get:

Therefore, the total charge enclosed by a sphere of radius r is

Now, by Gauss Law, flux emerging out of the surface is equal to times the total charge enclosed:

where

E = electric field

when earth is in rotational motion around the sun,it displaces from its place.

when a ball is placed on an inclined surface it does both the rotational and circular motion.

explanation:

to treat tumors in the body