Two people, that are 10.4 m apart, stretch a rope (2.31 kg) with a tension of 74.4 n. if one person sends a pulse through the rope, how long will it take for the resulting disturbance to reach the other end? a. 0.5 sec b.0.585 sec c.0.54 sec d.0.568 sec

Option D. 0.568 s

Given:

Length of the rope, l = 10.4 m

mass of the rope, M = 2.31 kg

Tension, T = 74.4 N

Solution:

The velocity of the wave, is given as:

Putting the values in the above formula:

Time taken, t can be calculated as:

Since distance between two end is the length of the rope

Therefore, using the formula for time, t:

t = 0.568 s

therefore, time taken for the disturbance to travel from one end to the other is t = 0.568 s