Alaser beam enters a 12.0 cm thick glass window at an angle of 33.0° from the normal. the index of refraction of the glass is 1.41. at what angle from the normal does the beam travel through the glass? how long does it take the beam to pass through the plate?

The time is 0.563 ns.

Explanation:

Given that,

Index of refraction of glass = 1.41

Distance = 12.0 cm

Angle = 33.0°

We need to calculate the refraction angle

Using Snell's law

put the value into the formula

We need to calculate the velocity of beam in glass

Using formula of velocity

Put the value into the formula

We need to calculate the time

Using formula of distance

Hence, The time is 0.563 ns.

the body's situation won't change the forces are equal opposit and on the same body

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.