Atrain accelerates from a station with a = 1.418m/s? upon reaching a speed of 16.89m/s the train travels at a constant velocity for a period. the train slows down as it approaches the next station at a rate of 2m/s 2 and stops at that station hint: sketch a graph of uversus tfor the train's journey. (a) if the two stations are 1,200m apart, how long does the train journey take?

81.22 s

Explanation:

Period during which train accelerates  t

=

=11.91 s

distance travelled during acceleration

= 1/2 a t² =.5 x 1.418 x 11.91² =100.57 m

Train decelerates during the period

=

= 8.445

Distance travelled during the period of deceleration

= v² /2 a = 16.89² / 2 x 2 =71.32 m.

Distance during which train travels uniformly

= 1200 - ( 100.57 + 71.32 ) = 1028.11 m

time taken in this part of journey

=

= 60.87 s

Total journey period = 60.87 + 8.445 + 11.91 =  81.22 s

we can see how the government has failed them.

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min