Aparticle of mass 2.4×10^−6 kg and charge 27 μc is moving at a speed of 27 m/s perpendicularly to a uniform 9.5-t magnetic field. what is the radius of the particle’s circular path?

0.253 m

Explanation:

Given that, the mass of the particle, .

Charge of the particle, .

Speed of the particle, .

Magnetic field is, .

The radius of the particle's circular path when the speed of the particle is perpendicular to the magnetic field is,

.

By putting all the values in the above equation.

.

Therefore by further solving,

Therefore the radius of the particle in a circular path is 0.253 m

i think it is non rem sleep

the total distance traveled by the car is

30km + 49km = 79 km .