Acar (mass 5 1100 kg) is traveling at 32 m/s when it collides headon with a sport utility vehicle (mass 5 2500 kg) traveling in the opposite direction. in the collision, the two vehicles come to a halt. at what speed was the sport utility vehicle traveling?

speed was the sport utility vehicle traveling is 14.08 m/s

Explanation:

Given data

car mass m1 = 1100 kg

speed s = 32 m/s

vehicle mass m2 = 2500 kg

to find out

speed was the sport utility vehicle traveling

solution

we will apply here conservation of momentum law

the momentum change of car  is equal  and opposite of the momentum change of vehicle

so equation are

m1 v1 - m2 v2 = 0

so here v2 will be

v2 = (m1 / m2 ) v1

put here all these value we get

v2 = (1100 /  2500 ) 32

v2 =  14.08 m/s

so speed was the sport utility vehicle traveling is 14.08 m/s

the answer to your question is high voltage and high currency

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.