Acircular loop of wire 78 mm in radius carries a current of 114 a. find the (a) magnetic field strength and (b) energy density at the center of the loop.

Explanation:

It is given that,

Radius of loop, r = 78 mm = 0.078 m

Current, I = 114 A

(a) Magnetic field strength of the circular loop is given by :

B = 0.000918 T

or

(b) Energy density at the center of the loop is given by :

Hence, this is the required solution.

the answer is 46 mls because when you add the speed per second it increses the speed

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west