Aperson's prescription for her new bifocal glasses calls for a refractive power of -0.500 diopters in the distance-vision part, and a power of 1.75 diopters in the close-vision part. what are the near and far points of this person's uncorrected vision? assume the glasses are 2.00 cm from the person's eyes, and that the person's near-point distance is 25.0 cm when wearing the glasses.

Far point = 202 cm

Near point = 38.5 cm

Explanation:

For distance vision we know that

we know that

now by lens formula we know that

so we have an object positioned at infinite we have

now distance from eye is given as

Now similarly for near point given at 25 cm from eye

the distance of the image should be 25 - 2 = 23 cm

power for near point is given as

now again by lens formula

b

step-by-step explanation: a third of 24 is 8, 8 times 3 is 24 so 8 - 2 would be 6

powerful computers now, not then