Water, of density 1000 kg/m3, is flowing in a drainage channel of rectangular cross-section. the width of the channel is 15 m, the depth of the water is 8.0 m and the speed of the flow is 2.5 m/s. at what rate is water flowing in this channel?

Water flowing rate=  (300000kg/s) = (300000l/s)

Explanation:

First with the section of the channel, the depth of the water and the speed of the fluid we can determine the volume of fluid that circulates per second through the channel:

Volume per time= 15m × 8m × (2.5m/s)= 300 m³/s

With this volume of circulating fluid per second elapsed, we multiply it by the density of the water to determine the kilograms or liters of water that circulate through the channel per second elapsed:

Water flowing rate= (300m³/s) × (1000kg/m³)= (300000kg/s) = (300000l/s)

Taking into account that 1kg of water is approximately equal to 1 liter of water.

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle

k2s for potassium sulphide