An object's weight is equal to its buoyant force in water. what would you expect to happen when the object is placed in water? explain your reasoning.

It will keep floating on the surface with a part of the body inside the liquid and a part outside it.

Explanation:

The Archimedes principle is the physical principle that states: a body totally or partially submerged in a fluid at rest, experiences an upward vertical thrust equal to the weight of the volume of fluid dislodged by the body. This force 1 is called hydrostatic thrust or Archimedes, and is measured in Newtons (in the SI). The Archimedes principle is formulated as follows:

flotation force  = liquid density  × force of gravity  × volume of liquid dislodged

Therefore in this case when placing a body in water whose weight is equal to the buoyant force, it will float in equilibrium on the surface of the liquid, since the volume of liquid that it displaces is equal to the weight of the body and this force of below upwards it keeps it on the surface with a part of the body inside the liquid and a force part of it. This is because only the volume of the necessary object is submerged to move the liquid corresponding to a buoyant force equal to its own weight.

i really dont know but i will try okay.

so i think u would just add all them up and get your answer..

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//